Input:
[
[ 1, 2, 3 ],
[ 4, 5, 6 ],
[ 7, 8, 9 ]
]
Output: [1,2,3,6,9,8,7,4,5]
Input:
[
[1, 2, 3, 4],
[5, 6, 7, 8],
[9,10,11,12]
]
Output: [1,2,3,4,8,12,11,10,9,5,6,7]
class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
vector<int> ans;
if (matrix.empty()) return ans;
for (int i = 0; i < (min(matrix[0].size(), matrix.size())+ 1) / 2; i++){
int x = i, y = i, width = matrix[0].size() - 2 * i, height = matrix.size() - 2 * i;
for (int j = x; j < width + x; ++j) ans.push_back(matrix[y][j]);
for (int j = y + 1; j < y + height - 1; ++j) ans.push_back(matrix[j][width + x - 1]);
for (int j = width + x - 1; j >= x && height > 1; j--) ans.push_back(matrix[y + height - 1][j]);
for (int j = y + height - 2; j > y && width > 1; j--) ans.push_back(matrix[j][x]);
}
return ans;
}
};