The between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note:
0 ≤ x, y < 231.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
Solution
class Solution {
public:
int hammingDistance(int x, int y) {
int z = x ^ y;
int count = 0;
while (z > 0) {
if ((z & 1) == 1) count++;
z >>= 1;
}
return count;
}
};