Given two binary trees, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical and the nodes have the same value.
Input: 1 1
/ \ / \
2 3 2 3
[1,2,3], [1,2,3]
Output: true
Input: 1 1
/ \
2 2
[1,2], [1,null,2]
Output: false
Input: 1 1
/ \ / \
2 1 1 2
[1,2,1], [1,1,2]
Output: false
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if (p == nullptr) return q == nullptr;
if (q == nullptr) return p == nullptr;
return (p->val == q->val) && isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
}
};